Tools › Structures › Joints › Adhesive Bonded Joint › Example
Balanced 2024-T3 double-lap bonded joint: Volkersen peak, Hart-Smith elastic-plastic strength, plateau and peel
| Tool | Adhesive Bonded Joint |
| Source | Hart-Smith, L. J. (1973). Adhesive-Bonded Double-Lap Joints. NASA Contractor Report 112235, National Aeronautics and Space Administration, Langley Research Center, Hampton, VA. Equations (22), (83), (112), (113) and the material properties of Table II (p. 80). |
| Level | Professional |
Problem
Two 0.125 in 2024-T3 splice plates are bonded to a 0.25 in 2024-T3 plate over a 2.5 in overlap with the ductile film adhesive of NASA CR-112235 Table II (τ_p = 6 ksi, bond thickness 0.005 in, γ_p/γ_e = 20). The joint carries an ultimate tensile load of 12,000 lb/in. Find the elastic (Volkersen) peak shear stress, the elastic-plastic state of the adhesive, the adhesive shear strength at this overlap and on the long-overlap plateau, the peel stress at the ends of the splice plates and the margins of safety.
Inputs to Enter
- Double lap, overlap L = 2.5 in, P = 12,000 lb/in entered as an ultimate load, no temperature change
- Adherends: t_1 = 0.125 in (each outer), t_2 = 0.25 in (inner), E = 10.5 Msi, F_tu = 65 ksi, F_ty = 47 ksi, ν = 0.3
- Adhesive: η = 0.005 in, G = 60 ksi, τ_p = 6 ksi (γ_e = 0.10), γ_p = 2.0, E_c′ = 500 ksi, peel strength 10 ksi
- FS = 1.5, FS_yld = 1.15
Answers
- λ = √((G/η)(1/(E_1 t_1) + 2/(E_2 t_2))) = 4.276 1/in, λL = 10.69; average stress 2.400 ksi; elastic peak (P/2)(λ/2) coth(λL/2) = 12.83 ksi; the adhesive first yields at 5,612 lb/in
- Elastic-plastic state at 12,000 lb/in: plastic zones 0.2663 in at each end, elastic zone 1.9675 in, end strain 0.279 against a failure strain of 2.10, trough stress 3.0 % of τ_p
- Adhesive shear strength at this overlap 30,000 lb/in (fully plastic, 2 τ_p L); plateau P = 4 √(E t) √(τ_p η (γ_e/2 + γ_p)) = 35,937 lb/in (CR-112235 eq. 22)
- Design overlap P/(2 τ_p) + 2/λ = 1.468 in (eq. 112); plastic zones + 6/λ = 1.936 in (MIL-HDBK-17-3F)
- Peel σ_c = τ_p (3 E_c′ (1 − ν²) t_o / (E_o η))^¼ = 8.056 ksi (eq. 83)
- M.S.: adhesive shear +1.50 (ULT), peel +0.24 (ULT), adherends F_tu +0.35 (ULT), F_ty +0.28 (LIM)
Notes
The tool's default inputs are this joint; press Submit. The joint is illustrative: the adhesive and aluminum properties are those of CR-112235 Table II (with γ_e 0.10 and γ_p 2.0, η(γ_e/2 + γ_p) = 0.01025 in against the table's 0.0102 in), the geometry and load are the tool's own. The report prints no dimensional worked example; the tool reproduces its non-dimensional strength tables (Appendix A.2) in test_bonded_joint.php.