Tools › Aerodynamics › Atmosphere and Flight Conditions › Standard Atmosphere and Airspeeds › Example
35,000 ft at 250 knots calibrated airspeed: the 1976 standard atmosphere and the airspeed chain of NACA Report 837
| Tool | Standard Atmosphere and Airspeeds |
| Source | National Oceanic and Atmospheric Administration, National Aeronautics and Space Administration, and United States Air Force (1976). U.S. Standard Atmosphere, 1976. NOAA-S/T 76-1562 (NASA TM X-74335), U.S. Government Printing Office, Washington, DC. Tables I, III and IV; Aiken, W. S., Jr. (1946). Standard Nomenclature for Airspeeds With Tables and Charts for Use in Calculation of Airspeed. NACA Report 837, eqs. (1), (2), (6), (9)–(14) and Table II. |
| Level | Undergraduate |
Problem
An airplane flies at 35,000 ft geometric altitude on a standard day with 250 knots calibrated airspeed. Find the temperature, pressure, density, speed of sound and viscosity of the air from the 1976 U.S. Standard Atmosphere, then the impact pressure the indicator senses, the Mach number, the true and equivalent airspeeds, the compressibility correction, the dynamic pressure and the Reynolds number per foot.
Inputs to Enter
- Altitude 35,000 ft, ISA + 0; airspeed given as CAS = 250 knots; reference length 1 ft
Answers
- Geopotential altitude H = r₀h/(r₀ + h) = 34,941 ft (10,650.1 m); troposphere, T = 288.15 − 0.0065 H = 218.924 K (−65.6 °F), the standard's Table IV row 35,000 ft: 218.924 K
- p = p₀ (T/T₀)^5.2559 = 23,908.9 Pa = 499.35 lb/ft² (Table IV: 2.3908 × 10² mb, p/p₀ 0.23596); ρ = p/(RT) = 0.38046 kg/m³ = 0.0007382 slug/ft³ (Table IV: 0.38046, ρ/ρ₀ 0.31058)
- a = √(γRT) = 296.61 m/s = 576.57 kt; Sutherland μ = 1.4341 × 10⁻⁵ Pa·s, ν = 3.7694 × 10⁻⁵ m²/s
- q_c = p₀[(1 + 0.2 (V_c/a₀)²)^3.5 − 1] = 219.26 lb/ft² (Report 837 Table II: 219.6 with its 1925 constants); M = √(5[(q_c/p + 1)^(2/7) − 1]) = 0.7403
- TAS = M a = 426.83 kt; EAS = TAS √σ = a₀ M √δ = 237.87 kt; compressibility correction EAS − CAS = −12.13 kt; q = 0.7 p M² = 191.56 lb/ft²
- Re/L = TAS/ν = 1.7756 × 10⁶ per foot; total temperature T(1 + 0.2 M²) = 242.92 K
Notes
The tool's default inputs are this case; press Submit. The atmosphere values reproduce every printed digit of the standard's Tables I, III and IV at the rows read (test_standard_atmosphere.php, 218 checks; References/Standard-Atmosphere/checks/atmos_check.py in numpy gives the same chain). Switching to SI gives 10,668 m, 23,908.9 Pa, 0.38046 kg/m³, 296.61 m/s and the same knots.